# Working with Operators and Control Flow in C#

In this chapter, you will learn about operators, control flow statements, and the C# preprocessor. **Operators** provide syntax for performing different calculations or actions appropriate for the operands within the calculation. **Control flow statements** provide the means for conditional logic within a program or looping over a section of code multiple times. After introducing the `if` control flow statement, the chapter looks at the concept of Boolean expressions, which are embedded within many control flow statements. Included is mention of how integers will not cast (even explicitly) to `bool` and the advantages of this restriction. The chapter ends with a discussion of the C# preprocessor directives.

## Operators

Now that you have been introduced to the predefined data types (refer to Chapter 2), you can begin to learn more about how to use these data types in combination with operators in order to perform calculations. For example, you can make calculations on variables that you have declared.

#### Listing 3.1. A Simple Operator Example

`int`

difference = 4 – 2;

Operators are generally broken down into three categories: unary, binary, and ternary, corresponding to the number of operands 1, 2, and 3, respectively. This section covers some of the most basic unary and binary operators. Introduction to the ternary operator appears later in the chapter.

### Plus and Minus Unary Operators (`+`, `-`)

Sometimes you may want to change the sign of a numerical value. In these cases, the unary minus operator (`-`) comes in handy. For example, Listing 3.2 changes the total current U.S. debt to a negative value to indicate that it is an amount owed.

#### Listing 3.2. Specifying Negative Values^{1}

//National Debt to the Penny`decimal`

debt = -15236332233848.35M;

Using the minus operator *is equivalent to subtracting the operand from zero.*

The unary plus operator (`+`) rarely^{2} has any effect on a value. It is a superfluous addition to the C# language and was included for the sake of symmetry.

### Arithmetic Binary Operators (`+`, `-`, `*`, `/`, `%`)

Binary operators require two operands. C# uses infix notation for binary operators: The operator appears between the left and right operands. The result of every binary operator other than assignment must be used somehow: for example, by using it as an operand in another expression such as an assignment.

The subtraction example in Listing 3.3 is an example of a binary operator—more specifically, an arithmetic binary operator. The operands appear on each side of the arithmetic operator and then the calculated value is assigned. The other arithmetic binary operators are addition (`+`), division (`/`), multiplication (`*`), and remainder (`%`)—sometimes called the mod operator.

#### Listing 3.3. Using Binary Operators

`class`

Division {`static void`

Main() {`int`

numerator;`int`

denominator;`int`

quotient;`int`

remainder; System.Console.Write(`"Enter the numerator: "`

); numerator =`int`

.Parse(System.Console.ReadLine()); System.Console.Write(`"Enter the denominator: "`

); denominator =`int`

.Parse(System.Console.ReadLine());`quotient = numerator / denominator;`

`remainder = numerator % denominator;`

System.Console.WriteLine(`"{0} / {1} = {2} with remainder {3}"`

, numerator, denominator, quotient, remainder); } }

Output 3.1 shows the results of Listing 3.3.

**Output 3.1.**

Enter the numerator: 23 Enter the denominator: 3 23 / 3 = 7 with remainder 2

In the highlighted assignment statements above, the division and remainder operations are executed before the assignments. The order in which operators are executed is determined by their **precedence** and **associativity.** The precedence for the operators used so far is as follows.

`*`,`/`, and`%`have highest precedence.`+`and`-`have lower precedence.`=`has the lowest precedence of these six operators.

Therefore, you can assume that the statement behaves as expected, with the division and remainder operators executing before the assignment.

If you forget to assign the result of one of these binary operators, you will receive the compile error shown in Output 3.2.

**Output 3.2.**

... error CS0201: Only assignment, call, increment, decrement, and new object expressions can be used as a statement

#### Using the Addition Operator with Strings

Operators can also work with non-numeric operands. For example, it is possible to use the addition operator to concatenate two or more strings, as shown in Listing 3.4.

#### Listing 3.4. Using Binary Operators with Non-Numeric Types

`class`

FortyTwo {`static void`

Main() {`short`

windSpeed = 42; System.Console.WriteLine(`"The original Tacoma Bridge in Washington\nwas "`

+`"brought down by a "`

+ windSpeed +`" mile/hour wind."`

); } }

Output 3.3 shows the results of Listing 3.4.

**Output 3.3.**

The original Tacoma Bridge in Washington was brought down by a 42 mile/hour wind.

Because sentence structure varies among languages in different cultures, developers should be careful not to use the addition operator with strings that require localization. Composite formatting is preferred (refer to Chapter 1).

#### Using Characters in Arithmetic Operations

When introducing the `char` type in the preceding chapter, we mentioned that even though it stores characters and not numbers, the `char` type is an **integral** type (“integral” means it is based on an integer). It can participate in arithmetic operations with other integer types. However, interpretation of the value of the `char` type is not based on the character stored within it, but rather on its underlying value. The digit `3`, for example, contains a Unicode value of `0x33` (hexadecimal), which in base 10 is `51`. The digit `4`, on the other hand, contains a Unicode value of `0x34`, or `52` in base 10. Adding `3` and `4` in Listing 3.5 results in a hexadecimal value of `0x167`, or `103` in base 10, which is equivalent to the letter `g`.

#### Listing 3.5. Using the Plus Operator with the `char` Data Type

`int`

n =`'3'`

+`'4'`

;`char`

c = (`char`

)n; System.Console.WriteLine(c);// Writes out g.

Output 3.4 shows the results of Listing 3.5.

**Output 3.4.**

g

You can use this trait of character types to determine how far two characters are from each other. For example, the letter `f` is three characters away from the letter `c`. You can determine this value by subtracting the letter `c` from the letter `f`, as Listing 3.6 demonstrates.

#### Listing 3.6. Determining the Character Difference between Two Characters

`int`

distance =`'f'`

–`'c'`

; System.Console.WriteLine(distance);

Output 3.5 shows the results of Listing 3.6.

**Output 3.5.**

3

#### Special Floating-Point Characteristics

The binary floating-point types, `float` and `double`, have some special characteristics, such as the way they handle precision. This section looks at some specific examples, as well as some unique floating-point type characteristics.

A `float`, with seven decimal digits of precision, can hold the value 1,234,567 and the value 0.1234567. However, if you add these two `float`s together, the result will be rounded to 1234567, because the exact result requires more precision than the seven significant digits that a `float` can hold. The error introduced by rounding off to seven digits can become large compared to the value computed, especially with repeated calculations. (See also the upcoming Advanced Topic, Unexpected Inequality with Floating-Point Types.)

Since the `double` can hold a more accurate value than the `float` can store, the C# compiler will actually evaluate this expression to `double number = 140.600006103516` because `140.600006103516` is the closest binary fraction to 140.6 as a `float`. This fraction is slightly larger than 140.6 when represented as a `double`.

Output 3.6 shows the results of Listing 3.7.

**Output 3.6.**

4.2 != 4.20000006258488 4.2 != 4.20000006258488 (float)4.2M != 4.2F 4.20000006258488 != 4.20000028610229 4.20000006258488 != 4.2 4.2F != 4.2D 4.19999980926514 != 4.2 4.2F != 4.2D

The `Assert()` methods alert the developer whenever their argument evaluates to `false`. However, of all the `Assert()` calls in this code listing, only half have arguments that evaluate to `true`. In spite of the apparent equality of the values in the code listing, they are in fact not equivalent due to the inaccuracies of a `float`.

You should be aware of some additional unique floating-point characteristics as well. For instance, you would expect that dividing an integer by zero would result in an error, and it does with data types such as `int` and `decimal`. The `float` and `double` types instead allow for certain special values. Consider Listing 3.8, and its resultant output, Output 3.7.

#### Listing 3.8. Dividing a Float by Zero, Displaying NaN

`float`

n=0f;// Displays: NaNSystem.Console.WriteLine(n / 0);

**Output 3.7.**

NaN

In mathematics, certain mathematical operations are undefined, including dividing zero by itself. In C#, the result of dividing the float zero by zero results in a special “Not a Number” value; all attempts to print the output of such a number will result in `NaN`. Similarly, taking the square root of a negative number with `System.Math.Sqrt(-1)` will result in `NaN`.

A floating-point number could overflow its bounds as well. For example, the upper bound of the `float` type is approximately 3.4 x 10^{38}. Should the number overflow that bound, the result would be stored as “positive infinity” and the output of printing the number would be `Infinity`. Similarly, the lower bound of a `float` type is –3.4 x 10^{38}, and computing a value below that bound would result in “negative infinity,” which would be represented by the string `-Infinity`. Listing 3.9 produces negative and positive infinity, respectively, and Output 3.8 shows the results.

#### Listing 3.9. Overflowing the Bounds of a `float`

// Displays: -InfinitySystem.Console.WriteLine(-1f / 0);// Displays: InfinitySystem.Console.WriteLine(3.402823E+38f * 2f);

**Output 3.8.**

-Infinity Infinity

Further examination of the floating-point number reveals that it can contain a value very close to zero, without actually containing zero. If the value exceeds the lower threshold for the `float` or `double` type, the value of the number can be represented as “negative zero” or “positive zero,” depending on whether the number is negative or positive, and is represented in output as `-0` or `0`.

### Compound Assignment Operators (`+=`, `-=`, `*=`, `/=`, `%=`)

Chapter 1 discussed the simple assignment operator, which places the value of the right-hand side of the operator into the variable on the left-hand side. Compound assignment operators combine common binary operator calculations with the assignment operator. Take Listing 3.10, for example.

#### Listing 3.10. Common Increment Calculation

`int`

x = 123;
x = x + 2;

In this assignment, first you calculate the value of `x + 2` and then you assign the calculated value back to `x`. Since this type of operation is relatively frequent, an assignment operator exists to handle both the calculation and the assignment with one operator. The `+=` operator increments the variable on the left-hand side of the operator with the value on the right-hand side of the operator, as shown in Listing 3.11.

#### Listing 3.11. Using the `+=` Operator

`int`

x = 123;
x += 2;

This code, therefore, is equivalent to Listing 3.10.

Numerous other combination assignment operators exist to provide similar functionality. You can also use the assignment operator with subtraction, multiplication, division and the remainder operators (Listing 3.12 demonstrates).

#### Listing 3.12. Other Assignment Operator Examples

x -= 2; x /= 2; x *= 2; x %= 2;

### Increment and Decrement Operators (`++`, `--`)

C# includes special unary operators for incrementing and decrementing counters. The **increment operator,** `++`, increments a variable by one each time it is used. In other words, all of the code lines shown in Listing 3.13 are equivalent.

#### Listing 3.13. Increment Operator

spaceCount = spaceCount + 1; spaceCount += 1; spaceCount++;

Similarly, you can also decrement a variable by one using the **decrement operator,** `--`. Therefore, all of the code lines shown in Listing 3.14 are also equivalent.

#### Listing 3.14. Decrement Operator

lines = lines - 1; lines -= 1; lines--;

The increment and decrement operators are used to control how many times a particular operation is performed. Notice also that in this example, the increment operator is used on a character (`char`) data type. You can use increment and decrement operators on various data types as long as some meaning is assigned to the concept of the “next” or “previous” value for that data type.

We saw that the assignment operator first computes the value to be assigned, and then causes the assignment. The result of the assignment operator is the value that was assigned. The increment and decrement operators are similar: They compute the value to be assigned, perform the assignment, and result in a value. It is therefore possible to use the assignment operator with the increment or decrement operator, though doing so carelessly can be extremely confusing. See Listing 3.16 and Output 3.10 for an example.

#### Listing 3.16. Using the Post-Increment Operator

`int`

count = 123;`int`

result;`result = count++;`

System.Console.WriteLine(`"result = {0} and count = {1}"`

, result, count);

**Output 3.10.**

result = 123 and count = 124

You might be surprised that `result` was assigned the value that was `count` *before* `count` was incremented. Where you place the increment or decrement operator determines whether the assigned value should be the value of the operand before or after the calculation. If you want the value of `result` to be the value assigned to `count`, you need to place the operator before the variable being incremented, as shown in Listing 3.17.

#### Listing 3.17. Using the Pre-Increment Operator

`int`

count = 123;`int`

result;`result = ++count;`

System.Console.WriteLine(`"result = {0} and count = {1}"`

, result, count);

Output 3.11 shows the results of Listing 3.17.

**Output 3.11.**

result = 124 and count = 124

In this example, the increment operator appears before the operand, so the result of the expression is the value assigned to the variable after the increment. If `count` is `123`, `++count` will assign `124` to count and produce the result `124`. By contrast, the postfix increment operator `count++` assigns `124` to `count` and produces the value that `count` held before the increment: `123`. Regardless of whether the operator is postfix or prefix, the variable `count` will be incremented before the value is produced; the only difference is which value is produced. The difference between prefix and postfix behavior appears in Listing 3.18. The resultant output is shown in Output 3.12.

#### Listing 3.18. Comparing the Prefix and Postfix Increment Operators

`class`

IncrementExample {`public static void`

Main() {`int`

x = 123;// Displays 123, 124, 125.System.Console.WriteLine(`"{0}, {1}, {2}"`

, x++, x++, x);// x now contains the value 125.// Displays 126, 127, 128System.Console.WriteLine(`"{0}, {1}, {2}"`

, ++x, ++x, x);// x now contains the value 128.} }

**Output 3.12.**

123, 124, 125 126, 127, 128

As Listing 3.18 demonstrates, where the increment and decrement operators appear relative to the operand can affect the result produced by the expression. The result of the prefix operators is the value that the variable had before it was incremented or decremented. The result of the postfix operators is the value that the variable had after it was incremented or decremented. Use caution when embedding these operators in the middle of a statement. When in doubt as to what will happen, use these operators independently, placing them within their own statements. This way, the code is also more readable and there is no mistaking the intention.

### Constant Expressions and Constant Locals

The preceding chapter discussed literal values, or values embedded directly into the code. It is possible to combine multiple literal values in a **constant expression** using operators. By definition, a constant expression is one that the C# compiler can evaluate at compile time (instead of calculating it when the program runs) because it is composed entirely of constant operands. Constant expressions can then be used to initialize constant locals, which allow you to give a name to a constant value (similar to the way local variables allow you to give a name to a storage location). For example, the computation of the number of seconds in a day can be a constant expression that is then used in other expressions by name.

The `const` keyword in Listing 3.19 declares a constant local. Since a constant local is by definition the opposite of a **variable**—“constant” means “not able to vary”—any attempt to modify the value later in the code would result in a compile-time error.

Note that the expression assigned to `secondsPerWeek` is a constant expression because all the operands in the expression are also constants.